Gjúp mjh haj pàj hoa nj zs maj kt ruj?

1)

mol NO2=2,24/22,4=0,1

=>mol HN03=0,1

mol NaOH=0,2*0,5=0,1

2NO2 +1/2O2+H2O=>2HNO3

HNO3 +NaOH =>NaN03+ H2O

vj

HN03 pư voj NaOH theo tj le 1:1

mà mol HN03=mol NaOH=0,1

suy ra pư 2 trung hoà

vay pH dd X=7(tao muoj trung hoa,pư ko du axjt,bazo nao)

2.

Vi d=1,787g/ml

gja sư m=1,787 g

=> V=1 ml=0,001 lit

khj m=1,787

suy ra

m H2SO4=1,787*86%=1,53682 g

=> mol H2SO4 =1,53682/98

vay

[H2SO4]=mol/lit=15,68 M

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2NO2 + 1/2O2 + H2O -> 2HNO3

HNO3 + NaOH -> NaNO3 + H2O

2) Bai nay hinh nhu ban ghi thieu de thi fai, ban kiem tra lai de di!