Math Question : Please help !?

Camaro = 65 mph

Harley = 50 mph

2.4 hours driven

36 (difference in distance driven) / 15 (difference in speed) = 2.4 (time driven)

156 / 2.4 = 65

120 / 2.4 = 50

Let:

s1 = speed of Sean's Camaro

s2 = speed of Rita's Harley

The relationship between s1 and s2 is:

s1 = s2 + 15 (Sean's Camaro equals the speed of Rita's Harley but 15 mph faster)

Let:

d1 = distance traveled by Sean (156 mi)

d2 = distance traveled by Rita (120 mi)

Use the "distance = rate*time" formula as it applies to Sean and Rita respectively:

d1 = s1*t1 (the distance traveled by Sean equals his speed times the time traveled)

d2 = s2*t2 (the distance traveled by RIta equals her speed times the time traveled)

However, both Sean and Rita travel over the same duration of time, meaning t1 = t2. Solve both equations simultaneously to find s1 and s2 (which represent Sean and Rita's speeds respectively).

d1 = s1*(d2/s2)

d1*s2 = s1*d2

(156 mi)*(s1 - 15) = s1*120

156*s1 - 2340 = 120*s1

36*s1 = 2340

==>s1 = 65 mph

s1 = s2+15

65 = s2 + 15

==>s2 = 50 mph

So, Sean's speed is 65 mph and Rita's speed is 50 mph.

I would divide 156 by 120.

yeah, Why is Rita driving a Harley in the kitchen?