Solve the equation 3(8x-24)=4(18x-6)?

This is just simple algebra

3(8x–24) = 4(18x–6)

24x – 72 = 72x – 24

72x – 24x = – 72 + 24

48x = – 48

x = –1

check

3(8x–24) = 4(18x–6)

3(8(–1)–24) = 4(18(–1)–6)

3(–8–24) = 4(–18–6)

3(–32) = 4(–24)

–96 = –96

ok

3(8x - 24) = 4(18x - 6)

24x - 72 = 72x - 24

- 48x = 48

x = - 1.

3(8x-24)=4(18x-6) (use the distributive property)

24x-72=72x-24 (factor 24 from both sides)

24(x-3)=24(3x-1) (divide both sides by 24)

x-3=3x-1 (add 1 to both sides)

-2+x=3x (subtract 3x on both sides)

-2-2x=0 (add 2 to both sides)

-2x = 2 (divide both sides by -2)

x=-1

3(8x-24)=4(18x-6)

24(x-3)=24(3x-1)

(x-3)=(3x-1)

x-3=3x-1

-2=2x

x=-1

Bryan is wrong

24x-72=72x-16

24x-56=72x

-56=48x

-56/48=x

-7/6=x

-71 =x did it mentally