Yahoo Hỏi & Đáp sẽ ngừng hoạt động vào ngày 4 tháng 5 năm 2021 (Giờ Miền Đông nước Mỹ) và từ nay, trang web Yahoo Hỏi & Đáp sẽ chỉ ở chế độ đọc. Các thuộc tính hoặc dịch vụ khác của Yahoo hay tài khoản Yahoo của bạn sẽ không có gì thay đổi. Bạn có thể tìm thêm thông tin về việc Yahoo Hỏi & Đáp ngừng hoạt động cũng như cách tải về dữ liệu của bạn trên trang trợ giúp này.
Gene linkage, find genotype/phenotype of parents given progeny?
A plant has 3 genes? that control colour.
P purple > p1 light purple > p white.
The number of leaves is controlled by 2 genes?
F five leafs > f four leafs
I cross a purple leaf with five leafs to white flower with four leafs.
F1 Progeny:
35 purple and five leafs
36 light purple and five leafs.
1) What is the genotype of the parents crossed?
I just had this on a test, hopefully I have all the information!
I guessed the parents :(
The dot means we don't know if genes are linked.
My punnet square for the hypothesized parent genotype:
P/p1 ⋅ F/F x p/p ⋅ f/f
.........P ⋅ F...........P ⋅ F...........p1 ⋅ F............p1 ⋅ F
p ⋅ f...P/p ⋅ F/f......P/p ⋅ F/f......p1/p ⋅ F/f......p1/p ⋅ F/f
Hope the above is understandable!
Progeny is 1/4 for all:
P/p ⋅ F/f
P/p ⋅ F/f
p1/p ⋅ F/f
p1/p ⋅ F/f
So half are Purple with five leafs
Other half are light purple with five leafs!
Parents must be: P/p1 ⋅ F/F and p/p ⋅ f/f?
Also: I'm learning about gene linkage, is there anyway to know if genes are linked? There was a part 2 crossing F1 with something, but I forgot what the question was specifically :(
1 Câu trả lời
- JazSincLv 73 năm trướcCâu trả lời yêu thích
Okay. I think you meant "alleles" instead of "genes" above.
I will proceed as if that is the case.
We know that your white flower plant is pp
There're light purple progeny so your purple flower plant is Pp1
So we have Pp1 x pp => Pp Pp p1p p1p looking good so far.
Your four-leaf parent is ff
ALL your progeny are five-leaf. Therefore your five-leaf parent is FF.
FF x ff => Ff Ff Ff Ff
Let's put them all together:
Pp1FF x ppff (answer)