Can you please help to find these areas  ?

A = [3*(3)^(1/2)/4]*r^2 Area equilateral triangle = 459.132 cm^2

A = of a Circle = pir^2 = 1109.8 cm^2

 the area of the three segments surrounding the triangle = pir^2 - [3*(3)^(1/2)/4]*r^2

1109.8 -  459.132 = 650.668 cm^2

(a)

R = 18.8, radius of circle

R = a/sqrt(3)

a = R*sqrt(3)

a = 18.8*sqrt(3)

a^2 = 1060.32

A = (sqrt(3)/4)a^2

A = (sqrt(3)/4)*1060.32

A = 265.08*sqrt(3) cm^2

A =~ 459.13202807035799296825547620638 cm^2

https://en.wikipedia.org/wiki/Equilateral_triangle

(b)

Area of circle: pi * 18.8^2 = 353.44*pi

Area of triangle: 256.08*sqrt(3)

Area of circle outside the triangle:

353.44*pi - 256.08*sqrt(3) =~ 666.82093668253842487572821825348